In order to remove an XML tag that contains just a number using Groovy, you can use the XmlSlurper class to parse the XML document and navigate through the nodes. You can then check if the content of the tag is a number and remove it accordingly.
Here is an example code snippet showing how you can achieve this:
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def xml = ''' <root> <tag1>abc</tag1> <tag2>123</tag2> <tag3>xyz</tag3> </root> ''' def rootNode = new XmlSlurper().parseText(xml) rootNode.'**'.findAll { it.text() ==~ /\d+/ }.each { it.parent().replaceNode {} } println groovy.xml.XmlUtil.serialize(rootNode) |
In this code snippet, we first parse the XML document using XmlSlurper and then iterate through all the nodes to find the ones that contain only numbers. We use a regular expression \d+
to check if the content is a number. If a node is found with just a number, we remove it by replacing its parent node with an empty closure.
After running this code, the XML document will be updated with the tags containing just a number removed.
How to strip an xml tag with a numeric value in Groovy efficiently?
One way to strip an XML tag with a numeric value in Groovy efficiently is by using the XmlSlurper
class provided by Groovy. Here is an example code snippet that demonstrates how to do this:
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def xmlString = ''' <root> <tag1>123</tag1> <tag2>abc</tag2> </root> ''' def root = new XmlSlurper().parseText(xmlString) root.'**'.findAll { it.text().isNumber() }.each { it.parent().remove(it) } def outputXml = XmlUtil.serialize(root) println outputXml // Function to check if a string is numeric String.metaClass.isNumber = { try { Float.parseFloat(delegate) return true } catch (NumberFormatException e) { return false } } |
In this code snippet:
- The XML string is parsed using XmlSlurper and stored in the root variable.
- The findAll method is used to find all elements in the XML that have a numeric value, and the remove method is called on each of these elements' parents to remove them.
- The XmlUtil.serialize method is used to convert the modified XML back to a string.
- A custom isNumber method is added to the String class using the metaClass property to check if a string is numeric.
This code efficiently removes XML tags with numeric values from the input XML.
What is the most efficient method to eliminate an xml tag with only numbers using Groovy?
One efficient method to eliminate an XML tag containing only numbers using Groovy is to use the XmlSlurper class to parse the XML document and remove the tag based on a specified criteria. Here is an example code snippet that demonstrates this approach:
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def xml = """ <root> <tag1>123</tag1> <tag2>abc</tag2> <tag3>456</tag3> </root> """ def parsedXml = new XmlSlurper().parseText(xml) parsedXml.'**'.findAll { node -> // Check if the text content of the node contains only numbers node.text().matches(/^\d+$/) }.each { node -> // Remove the node from the XML document node.parent().replaceNode { } } def updatedXml = XmlUtil.serialize(parsedXml) println updatedXml |
In this example, the XmlSlurper class is used to parse the XML document and find all nodes that contain only numbers in their text content. The findAll
method is used to filter out these nodes, and then the each
method is used to iterate over them and remove them from the XML document using the replaceNode
method. Finally, the updated XML document is serialized back to a string using the XmlUtil class and printed to the console.
What is the best way to remove an xml tag containing only numbers with Groovy?
One way to remove an XML tag containing only numbers with Groovy is by using the XmlSlurper class to parse the XML and then filtering out the tags that contain only numbers. Here is an example code snippet that demonstrates how to achieve this:
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def xml = ''' <root> <tag1>abc123</tag1> <tag2>456</tag2> <tag3>789xyz</tag3> </root> ''' def slurper = new XmlSlurper().parseText(xml) def filteredXml = new StreamingMarkupBuilder().bind { mkp.yield slurper.root.children().findAll { node -> !node.text().matches("\\d+") } } println filteredXml.toString() |
In this example, the XML string xml
is parsed using XmlSlurper. The filteredXml
variable then uses a StreamingMarkupBuilder to create a new XML structure with only the tags that do not contain only numbers. The findAll
method is used to filter out the tags that contain only numbers using a regular expression \d+
, which matches one or more digits.
Finally, the filteredXml
is printed, which will output the following XML:
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<tag1>abc123</tag1> <tag3>789xyz</tag3> |
What is the appropriate method to delete an xml tag containing only numbers with Groovy?
One approach to delete an XML tag containing only numbers using Groovy is to leverage the XMLSlurper and MarkupBuilder classes. Here is an example code snippet illustrating how to achieve this:
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def xmlString = """ <root> <tag1>abc123</tag1> <tag2>456</tag2> <tag3>789</tag3> <tag4>xyz</tag4> </root> """ def xml = new XmlSlurper().parseText(xmlString) xml.'**'.findAll { node -> node.name() ==~ /^\w+$/ && node.text() ==~ /^\d+$/ }.each { node -> node.parent().replaceNode { out -> out.mkp.yieldGroovy("") } } def builder = new groovy.xml.MarkupBuilder().bind { root { xml.children() } } println builder.toString() |
In this code snippet, we first define a sample XML string containing various tags with text values. We then parse this XML string using the XmlSlurper class to create an XML object. We then use the findAll method to identify XML tags with names consisting of only word characters (letters, digits, or underscores) that contain only digits as text.
For each such tag found, we replace it with an empty string using the replaceNode method. Finally, we create a new XML structure excluding the deleted tags using the MarkupBuilder class.
Running this code snippet will result in an XML output where the and tags (which contain only numbers) have been removed.